(X/2+3)^2=(6+x/4)^2

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Solution for (X/2+3)^2=(6+x/4)^2 equation: 


x in (-oo:+oo)

t_1 = (X/2+3)^2

t_1-(x/4+6)^2 = 0

t_1-1*(1/4*x+6)^2 = 0

t_1-1*(1/4*x+6)^2 = 0

t_1-1/16*x^2-3*x-36 = 0

t_1-1/16*x^2-3*x-36 = 0

t_1-1/16*x^2-3*x-36 = 0

DELTA = (-3)^2-(-1/16*4*(t_1-36))

DELTA = 1/4*(t_1-36)+9

1/4*(t_1-36)+9 = 0

1/4*(t_1-36)+9 = 0

1/4*t_1 = 0

t_1/4 = 0

t_1/4 = 0 // * 4

t_1 = 0

t_1 = 0

DELTA = 0  <=>  t_4 = 0

x = 3/(-1/16*2) i t_1 = 0

x = -24 i t_1 = 0

( x = ((1/4*(t_1-36)+9)^(1/2)+3)/(-1/16*2) or x = (3-(1/4*(t_1-36)+9)^(1/2))/(-1/16*2) ) i t_1 > 0

( x = -8*((1/4*(t_1-36)+9)^(1/2)+3) or x = -8*(3-(1/4*(t_1-36)+9)^(1/2)) ) i t_1 > 0

t_1+0 > 0

t_1 > 0

t_1+0 > 0 // - 0

t_1 > 0

x in { -24, -8*((1/4*((X/2+3)^2-36)+9)^(1/2)+3), -8*(3-(1/4*((X/2+3)^2-36)+9)^(1/2)) }

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